Sunday, May 1, 2005

Pacing
Am I the only one out there whho would mathematically define the distance of a pace proportinal to the pacer for kicks? Unfortunately, some of my friends don't share my obsessions, especially when I rant on about them in Yahoo Messanger. I told one of my friends to walk 19.376 paces,and they replied with, "Can you walk 0.376 paces?"."Of course, the distance of a pace is not constant, like that of a foot or meter, but proportinal to the legs of the one pacing." Lets assume that the average person walks a pace with an angle of 30 degrees between their legs, as well as each foot being 75 degrees to the ground. This froms an icocesles triangle(assuming both legs are the same length) between the two legs(l), and the distance on the groud between them, of stride(s). The formula goes as follows(my computer is retarded so V=square root and {2}=squared:
1/3[V(l{2})2]=s. Yeah, It looks kind of random and complictated. lts start with the brackets. Now pythagorus says that on a 90 degree angle, the sum of the squares of the legs are equal to the square of the hypotenuse, for all those for which math is not your forte, |_ these two sides(legs), when they are multiplied by themselves and and then the new values are addedar equal to \ this part, when multipled by itself; a{2}+b{2}=c{2}. Say for the moment that instead of a 30 degree stride, a pace is 90 degrees. The ground being the hypotenuse, both a and b in this case(literally legs) are the same value: the length of a leg, or l. That means we can substitute l for both a and b:l{2}+l{2}=c{2}. This can be simplified further to 2(l{2})=c{2}. Treating this like an equation we can find the square root of 2(l{2}) and elimanate the sqaure on the opposite side:
V2(l{2})=c. But alas, an average pace is not 90, but 30 degrees. If we multiply both sides by ¨÷, than the equation becomes true for 30 degrees(1/3 of 90 is 30). This leaves us with 1/30[V(l{2})2]=1/3c. Say that value s is equal to 1/3c. This means 1/3[V(l{2})2]=s. Thus, we arrive at our original formula, despite the fact it should makee sense with actual mathematical symbols and such. Math is so fun, considering I'm the only one who'll understand geometry next year. Seriously, Andrew, send me that 1=2 equation.